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expect output overwrite

Posted by mansoorx (mansoorx), 6 May 2006
Through this code i just store the output in a file "/tmp/run.txt ".
But whenever i run this script previous contenets of the "/tmp/run.txt" file is overwrited.
How can i solve this problem

send "sh run int  Fa0/[lindex $argv 2]\r"
expect [lindex $argv 1]
set run [open /tmp/run.txt w+];
set tempvarl $expect_out(buffer);

Posted by admin (Graham Ellis), 6 May 2006
Open with a+ not w+

Posted by mansoorx (mansoorx), 6 May 2006
Thank You, very much.

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