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Specifying a log file name at the command prompt

Posted by skumar003 (skumar003), 7 May 2003
My executable(RUN) at the command prompt is as follows.

RUN contains the commands
execute port@host package

Package contains the scripts to run

In the execute file I am doing the following to create a log file
log_file -a -noappend results.log.

Whenever I perform RUN it creates a logfile results.log.

What I want to do from here is that have the option of specifying a log file when I say RUN

For Eg:

Run x.log --it should create log file named x.log
If I juat say RUN it by default creates results.log

How can I accomplish this? Can U please offer your thoughts.

Posted by admin (Graham Ellis), 7 May 2003
Command line parameters are held in the variable argv.
Here's an example which uses the last command line parameter as the file name if the command is run with parameters, and uses results.txt as the log file if you run it with no parameters at all

if {[llength $argv] > 0} {
       set logfile [lindex $argv end]
       } else {
       set logfile results.log

puts "Your log file is $logfile"

When you run that, you get

bash-2.04$ logfiledemo
Your log file is results.log
bash-2.04$ logfiledemo this.txt
Your log file is this.txt

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