Hi All,
I need help to convert a c shell script to perl.
Thanks for everyone.
Kobi.

#******** START SCRIPT *************
#!/bin/csh -cvx

source $1

echo "--0--"
echo $lnPARAM[0]
echo $lnVAL[0]
echo "--1--"
echo $lnPARAM[1]
echo $lnVAL[1]
echo "--2--"
echo $lnPARAM[2]
echo $lnVAL[2]
echo "--3--"
echo $lnPARAM[3]
echo $lnVAL[3]
echo "--4--"
echo $lnPARAM[4]
echo $lnVAL[4]
echo "--5--"
echo $lnPARAM[5]
echo $lnVAL[5]

exit
#******** ENND SCRIPT *************


Hi, Kobie .... your echos become prints and you add a semicolon on the end of each line.  The exit is unnecessary (in either language) and your source will probably become a require.

I have a saying "If you find yourself repeating something, there's probably an easier way" and I really the original script is rather nasty ... you didn't need all those echos!  What you create by doing a direct translation will be a rather nasty Perl script, and I would suggest you learn some Perl and rewrite it to a higher quality.  

Hi Graham Ellis,
Thank you for your quick answer  ,
My big problem is the line: source $1
What is the purpose of this line? and what should i use instead of it in perl?
Thanks again
Kobi

source $1

means "run the file named on the command line in the current script at this point".    The equivalent in perl would be:

require $ARGV[0];

and you'll need to rewrite the sourced / required file into Perl too.

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