| |||||||||||
| |||||||||||
RegEx problem - finding EOL Posted by jonnyr9 (jonnyr9), 16 May 2003 I need to detect if array elements contain line breaks and substitute them for nothing. I guess there is a special reference for these but can not find them. The end aim is clean a MySQL db of EOL chars.if(@row =~ m/(\\n)/){ print "Found EOL char in @row"; } What if the EOL originated in an html page. Posted by admin (Graham Ellis), 16 May 2003 I would use an s operator in a for loop on the list (as an alternative you could use a map which would be even shorter). Here's a sample program that reads a file into a list then takes all training white space off the end of each line and also the line separators, even when the line separators are embedded withing a multiline string within the @rows list. The program replaces the new line with a single space - put what you like in there of course but I guess you don't want the lines to run toghether!Code:
By the way - I know the test data isn't very good as it only has one new line on each list element and the whole ting could have been done with a chomp in this case. You also asked about HTML line ends .... For a paragraph tag: s/\s*<p\s.*?>/ /igs; will get rid of the "p tags" and replace them with a space This page is a thread posted to the opentalk forum
at www.opentalk.org.uk and
archived here for reference. To jump to the archive index please
follow this link.
|
| ||||||||||
PH: 01144 1225 708225 • FAX: 01144 1225 793803 • EMAIL: info@wellho.net • WEB: http://www.wellho.net • SKYPE: wellho |