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For 2023 (and 2024 ...) - we are now fully retired from IT training.
We have made many, many friends over 25 years of teaching about Python, Tcl, Perl, PHP, Lua, Java, C and C++ - and MySQL, Linux and Solaris/SunOS too. Our training notes are now very much out of date, but due to upward compatability most of our examples remain operational and even relevant ad you are welcome to make us if them "as seen" and at your own risk.

Lisa and I (Graham) now live in what was our training centre in Melksham - happy to meet with former delegates here - but do check ahead before coming round. We are far from inactive - rather, enjoying the times that we are retired but still healthy enough in mind and body to be active!

I am also active in many other area and still look after a lot of web sites - you can find an index ((here))
Match and Capture - Regular Expressions
Character Strings example from a Well House Consultants training course
More on Character Strings [link]

This example is described in the following article(s):
   • Learning about Regular Expressions in C through examples - [link]

Source code: reg2.c Module: C206
/* The C language comes with a regular expression engine as standard and
a header file in regex.h. In this example program, we ask the user to
enter a regular expression and then match it against a series of further
strings.

There is a shorter example at reg.c ... this example (reg2.c) caputures
the start and end point of each match and then prints out the string that
matches that part of the incoming string- "capture parenthises" */


#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <regex.h>

#define MAXMATCH 20

int main () {

        char reginald[81]; /* Regular Expresion */
        char millie[81]; /* Strings to match against */
        char tommy[81]; /* String to hold matched elememts */
        regex_t emma;

        regmatch_t matches[MAXMATCH]; /* Array of matches */
        int status;
        int i;
        int numchars;

        /* Read in and compile a regular expression */

        printf("Please give test expression: ");
        fgets(reginald,80,stdin);
        reginald[strlen(reginald)-1] = '\0';

        /* Let's use extended regular expresssions */

        status = regcomp(&emma,reginald,REG_EXTENDED);
        printf("Validity of regex (0 => OK): %d\n",status);

        /* Leave program if regex is faulty */
        /* we could use regerror to decode the error ... */
        if (status) return 1;

        while (1) {

                /* Loop until an empty line id given */

                printf("Please give test string: ");
                fgets(millie,80,stdin);
                millie[strlen(millie)-1] = '\0';
                if (strlen(millie) < 1) break;

                status = regexec(&emma,millie,MAXMATCH,matches,0);
                printf("Matched (0 => Yes): %d\n",status);
                if (status == 0) {
                        for (i=0; i<MAXMATCH; i++) {
                                if ((int)matches[i].rm_so < 0) break;
                                numchars = (int)matches[i].rm_eo - (int)matches[i].rm_so;
                                strncpy(tommy,millie+matches[i].rm_so,numchars);
                                tommy[numchars] = '\0';
                                printf("From %d to %d (%s)\n",(int)matches[i].rm_so,
                                        (int)matches[i].rm_eo,tommy);
                                }
                        }

                }

        /* Free up memory held within the regex memory */
        regfree(&emma);

        return 0;

        }

/* Sample output:

wizzard:c graham$ ./reg2
Please give test expression: [A-Z]{1,2}[0-9][0-9A-Z]? +[0-9][A-Z]{2}
Validity of regex (0 => OK): 0
Please give test string: We are at SN12 7NY for this course
Matched (0 => Yes): 0
From 10 to 18 (SN12 7NY)
Please give test string:
wizzard:c graham$

wizzard:c graham$ ./reg2
Please give test expression: ([A-Z]{1,2})[0-9][0-9A-Z]? +[0-9][A-Z]{2}
Validity of regex (0 => OK): 0
Please give test string: We are in Birmingham
Matched (0 => Yes): 1
Please give test string: We are at B12 7HJ
Matched (0 => Yes): 0
From 10 to 17 (B12 7HJ)
From 10 to 11 (B)
Please give test string:
wizzard:c graham$

*/



Learn about this subject
This module and example are covered on the following public courses:
 * Learning to Program in C
 * Learning to program in C and C++
 * Programming in C
 * C and C++ Programming
 * Learning to program in C and C++
 * C and C++ Programming
Also available on on site courses for larger groups

Books covering this topic
Yes. We have over 700 books in our library. Books covering C and C++ are listed here and when you've selected a relevant book we'll link you on to Amazon to order.

Other Examples
This example comes from our "Character Strings" training module. You'll find a description of the topic and some other closely related examples on the "Character Strings" module index page.

Full description of the source code
You can learn more about this example on the training courses listed on this page, on which you'll be given a full set of training notes.

Many other training modules are available for download (for limited use) from our download centre under an Open Training Notes License.

Other resources
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