Hi,
I'm modifying an existing page which was simply including the output from a perl script.

/contactus.php:
Code:

<? include ("http://mysite.com/cgi-bin/helpdesk/tx.cgi?cmd=newticket"); ?>

Now I need to pass a HTTP_REFERER value through to it to find where the user first clicked the contact button, so I am doing so in the url of contactus.php?refer=http://mysite.com/thispage.html, reading the file and trying to use preg_replace to put the value into the form in a hidden field using this in contactus.php:

[code]<?
$refer = $_GET['refer'];

$lines = file("http://mysite.com/cgi-bin/helpdesk/tx.cgi?cmd=newticket");
foreach ($lines as $line)
     { $find="/xRef/";
           $replace = $refer;
           preg_replace($find,$replace,$line);
           echo $line;
     }
?>

I don't get any errors, and it displays properly, but looking at the page source, it's not replacing the xRef value and I can't figure out why not, I can echo $refer at the top and can see the value is there. I expect it's just my first experience with preg_replace and I'm doing something silly.

preg_replace RETURNS the modified string rather that changing it "in situ".  

Try replacing
   preg_replace($find,$replace,$line);  
by
   $line = preg_replace($find,$replace,$line);  


Ah-hah! That did the trick, thank you Graham!

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