There *has* to be an elegant way to do this in Expect...

I have a command that returns lines of numbers. Like:

prompt% mycommand --loop=5
   9   4956   4951   4951   4956
   9   4960   4951   4951   4956
   9   4956   4951   4951   4956
   9   4956   4951   4951   4956
   9   4956   4951   4951   4956
prompt%

All numbers must be inside a given interval (eg. 4900-5000 in the case above). If they are not I must report which column that has the number outside the interval (column 0 above).

I could start a lot of bash and/or C programming, but I would rather keep it all in the Expect script that I am using to invoke the command from anyway.

Any suggestions?

If the numbers were in a file called tcs, which looked like this

Code:

9   4956   4951   4951   4956 9   4960   4951   4951   4956 9   4956   4851   5951   4956 9   4956   4951   4951   4756 9   4956   4951   4951   4956

You could write code like this

Code:

set fred [open tcs] set counter 0 while {[gets $fred line] > -1} {        incr counter        set cc 0        foreach number [lrange $line 1 end] {                incr cc                if {$number < 4900 || $number > 5000} {                        puts "Problem with $number - line $counter, column $cc"                }        } }

To produce results like this

Code:

earth-wind-and-fire:~/sep07 grahamellis$ tclsh nx Problem with 4851 - line 3, column 2 Problem with 5951 - line 3, column 3 Problem with 4756 - line 4, column 4 earth-wind-and-fire:~/sep07 grahamellis$

That should help you along.   If you're thinking you need to learn a lot more about what I have done, see here

It did help me along. Thanks a lot.

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